Wednesday, November 29, 2023

Bell's theorem is for ANY wave, not specifically for quantum mechanics

We have earlier in this blog claimed that Bell's theorem essentially states a very obvious fact that if you make a wave function to "collapse", the collapse destroys precious information, and you cannot reproduce the same interference pattern that you could produce with an "unharmed" wave.


Today we realized that actually this is true for any wave, also for classical waves. Consider the double-slit experiment. We can treat the laser beam as a classical electromagnetic wave, or alternatively, a probability amplitude wave of quantum mechanics (using the Feynman terminology).

If we disturb the wave, the interference pattern on the screen changes. A "collapse" of the wave is a drastic operation on an electromagnetic wave. It is like using a converter to transform an analog (real number) signal to a binary number 0 or 1.

A "hidden variable" hypothesis typically is incompatible with the hypothesis that we are dealing with a simple, undisturbed wave.


Non-locality


Bell's theorem is often interpreted as showing that quantum mechanics is "nonlocal". There is a "spooky action at a distance", to paraphrase Albert Einstein.

In this blog we do not believe in any spooky action at a distance. Rather, we believe that the wave function can only "collapse" inside the head of a single observer. Any measurement result made by any measuring apparatus is transmitted as a probability amplitude wave into the head of the observer, where the final collapse happens. It is like the double-slit experiment where the screen is placed inside the head of the single observer.

Sunday, November 26, 2023

Extra inertia inside a gravity field versus electric field

Our previous blog post required the assumption that if the charge Q is positive and q is negative, then the inertia of q is reduced inside the electric field of Q. Does this make sense?


                           ● Q

                • q -----------> 
            o/                           
             |                              
            /\                               

     observer 


Let the observer lower the negative test charge q close to Q. The inertia of q is reduced by

       2 |U| / c²,

where U is the potential energy of q in the field of Q?

This does not make sense. There is energy flowing in the common field of Q and q. A better hypothesis is the following.


A new conjecture of the inertia of a test charge q inside the electric field of another charge Q


Corrected conjecture about inertia inside an electric field. If Q and q have the same sign, and the potential of q is U, then the inertia of q in a radial movement relative to Q is

       2 U / c²

larger than in empty space. In a tangential movement it is U / c² larger. However, if the field of Q is canceled by a charge -Q close to it, then there is no excess inertia. If Q and q have a different sign, then the excess inertia is

       2 |U| / c²

in a radial movement and |U| / c² in a tangential movement.


Thus, an opposite electric field can reduce the extra inertia which would come from an electric field. This makes a lot of sense. The new formulation of the inertia rule says that the energy in the combined field of q, Q, and Q- is not "private". Also, the new formulation says that any interaction increases the inertia of q, or keeps it constant. This sounds good.

Assumption about paradoxical momentum exchange. When q and Q have the same sign, Q is static in the frame, and q gains more inertia I in the electric field of Q, that paradoxically speeds up the velocity of q by a factor

       1  +  I / m,

where I is the gained inertia and m is the inertial mass of q. If Q and q have different signs, then there is a slowdown of the velocity of q by a factor

       1  -  I / m.


The slowdown sounds reasonable. If Q is sitting still, and q gains more inertia from Q, we expect the velocity of q to slow down. The paradoxical assumption is required to make the magnetic field to guide q to the right direction when Q and q have the same sign. We have to think about this. Can we find a reasonable explanation for the momentum exchange in the paradoxical case?


How "private" is the Coulomb interaction?


                  v <-- • e- 
        ===============  wire


                        ^  V
                        |
                         • -----> V'
                        q = e-


Let q approach with the velocity V. The magnetic force accelerates q sideways. To explain the magnetic force, we first have to calculate the "inertia force" for the field of the electrons in the wire and then subtract the inertia force of the protons in the wire.

The inertia force is "private" in the movement of the electrons. We cannot first sum the electric fields of the electrons and the protons, since there would be no electric field at all. But at the end of the calculation we are allowed to subtract the inertia in the field of the protons from the inertia in the field of the electrons. In this phase, the interaction is "public".

The privacy definition is equivalent to traditional electromagnetism. A "moving" electric field induces a magnetic field. One can subtract electric fields, but that does not cancel the magnetic field.


The problem of the 1-2-3 wire: the electric field


On October 17, 2023 we tried to figure out the field of a mass flow of this form:


            1                                3
                \                          /    ^  v 
                  \                      /    /
                    \__________/     • e-
                                   2

                             ^   V 
                             |  
                             • q = e-
                               m


Let us analyze the analogous electric wire. The mass flow is replaced with an electron flow. The parts 1 and 3 point directly at q.











In our November 14, 2023 blog post we assume that v² is very small, and we can ignore it. Then γ = 1, and the corrections come from the product v • V in the Lorentz transformation formulae above, and from the inertial mass of the test charge q:

       m + 1/2 (V ± v)².

Let us analyze the part 1 of the wire. The electrons there are moving toward q at a velocity v, while the protons stand still. In the comoving frame of the electrons, q is moving at a larger velocity,

       V + v.

The Coulomb force Fc accelerates q in the comoving frame. Switch to the laboratory frame: the acceleration has a correction from the different inertial mass, as well as from the acceleration of the moving charge q.

We proved in the previous blog post that the Biot-Savart law holds for 1: there is no force on q. The Coulomb part in the laboratory frame is:

       ac  =  (Fc (1  -  v • V / c²)  -  V (Fc • v / c²))

                 /  (m + 1/2 m V² / c²),

and the "inertial force" part:

       ai = (-V (Fc • V / c²)  +  V (Fc • v / c²)

                + v (Fc • V / c²))

              /  (m + 1/2 m V² / c²).

In the Coulomb part, "1" is canceled by the Coulomb force from the protons. The acceleration term

       -Fc (v • V / c²)

points away from the part 1. The term 

       -V (Fc • v / c²)

points directly down. We can say that the Coulomb force of approaching electrons pushes q down, relative to the attraction of the protons. This sounds reasonable.

The first term in the inertia force is canceled by the protons. The second term cancels the third term of the Coulomb force. The third term cancels the second term of the Coulomb force. The inertia force pulls q up. This is a result of the paradoxical momentum exchange. Without the paradox, q would be pushed down.

The magnetic effect by the part 1 on q is zero. Is this a coincidence, or somehow "required" about a magnetic effect?

In this analysis, we analyzed the field of the electrons "privately". Only at the end we subtract the effect of the protons.

If we would do a "public" analysis, then we would conclude that there is no electric field in the laboratory frame, and consequently, there are no inertia effects whatsoever: no magnetic force.

However, the "public" method fails spectacularly for the part 2: it predicts that there is no magnetic field, which contradicts experiments.

We conclude that the "private" analysis is the correct one in the case of the electric field.


The 1-2-3 mass flow in gravity


In gravity, the analysis of the part 1 of the flow is different from an electric field. A major difference is that the gravity charge of the test mass depends on the velocity of the test mass, while the electric charge of q stays the same.

Another difference is that gravity modifies the spatial metric.


            1                                3
                \                          /    ^  v 
                  \  dm              /    /   mass flow
                    \__________/      
                                     2
                        r = distance (dm, m)
                             ^   V 
                             |  
                             • m


Let us compare the gravity of the mass flow to the case where the mass would be static. This is analogous to the electric version where the protons were static and the electrons moved.

Rather than doing the calculation here, let us write a separate blog post where we derive the "Biot-Savart law" for gravity.


Conclusions


We will continue from where we were left in this blog post, and we will derive the "Biot-Savart law" for gravity in a new blog post in December 2023. We will adapt the calculation of November 14, 2023 to include the main difference between gravity and the Coulomb field: the "gravity charge" of a test mass is m / sqrt(1  -  V² / c²).

Tuesday, November 14, 2023

Deriving electromagnetism from the inertia inside the electric field

UPDATE December 9, 2023: We still have problems with the "inertia force". If in a radial motion, we need to have the extra inertia 2 U, but the inertia force is defined as it would only be U. The calculations below are erroneous. We will write a new blog post in December 2023.

----

UPDATE November 27, 2023: We formulated a new inertia rule for an electric field where any interaction increases the inertia of q. See our November 26 blog post.

----

UPDATE November 24, 2023: We probably have to assume that the potential U between two negative charges dq and q increases the inertia of q, (and decreases, if dq is positive). This makes more sense than our previous claim that the repulsion between dq and q paradoxically reduces the inertia of q. That claim leads to a nonsensical result that an electron in a potential less than 511 kV would have negative inertia.

We also have to assume a "paradoxical momentum exchange" between dq and q.

----

In our September 23, 2023 blog post we asked if a mass flow coming directly toward a test mass m exerts a specific force on m, besides the usual gravity force.


                                   ^   v
                                 /
            ● dm          ● dm
              \    
                v    v 

                  



                       • m


If we have an individual mass dm approaching m, or receding from m, then the Schwarzschild solution says that the extra inertia of m in the field of both dm's in the diagram pushes m to the right in the diagram. An open question is what happens if there is a constant mass flow. The gravity field stays constant, though the individual mass elements change. Why should the inertia inside the field push m to some direction?

We have the exact same question about the electric field. In the case of the electric field, we may have empirical data which resolves the question. Let us check if the standard formulae for calculating the magnetic field of a coil include the effect from the inertia inside the electric field of a charge approaching a test charge directly.

Definition. An interaction is private if a flow of charge Q moving directly toward a test charge q causes an inertia effect on q that can be summed from the inertia effects of elementary charges dq in Q.


On September 4, 2023 we derived the magnetic field of a straight electric wire, using the Schwarzschild metric. We used the "privacy" assumption there. It contributed 2/3 of the acceleration to the direction of the wire. Let us check our calculations again.


The Biot-Savart law













The Biot-Savart law gives a zero magnetic field in the direction of a wire element dl, because of the factor dl × r'.

The magnetic force should depend on a non-zero velocity V of a test charge q in the laboratory frame. If q is static, and the extra inertia inside the field of Q pushes q, that is another kind of a force.


Changes in the inertia of a charge inside an electric field: assumptions


We assume that dq and q both have a negative charge. We use the hypothesis of our September 4, 2023 blog post, but with the sign flipped:

Conjecture about inertia inside an electric field. If q and dq have the same sign, then the inertia of q relative to dq in a tangential motion, inside the electric field of dq, is increased by the potential energy

       U  =  1 / c²  *  1 / (4 π ε₀)  *  |q| |dq| / r²,

where r is the distance between q and dq. In a radial motion the inertia increase is double of that: 2 U.

If q and dq have different signs, then the inertia decreases by U.


Assumption about the "inertia force". The inertia U "has the velocity of" dq when q acquires it. In a radial motion, only a half of the extra inertia 2 U has the velocity of dq.


Assumption about paradoxical momentum exchange. When q gains more inertia in the electric field of dq, and the charges of q and dq have the same sign, that paradoxically speeds up the velocity of q relative to dq. The sign of the inertia force is flipped.


The paradoxical assumption is required to get the sign right in the magnetic force. The assumption really is paradoxical because if dq and q have the same sign, and q approaches dq, we would expect the extra inertia of q to slow down the movement of q relative to dq.

We use the paradoxical assumption to derive the magnetic force, which never speeds up the velocity of q. Thus, we do not need to face the problem from where q would acquire the energy for the speedup in its velocity. The paradoxical assumption might be associated with the hypothesis that positrons are electrons moving backward in time. We have to investigate that.

If the electrons do not move, then there should be no change in inertia. That happens because the changes in the inertia of q due to dq and -dq cancel each other out.

But why should we take into account the inertia when the electrons move in the wire? Is the inertia "private" to each dq, and if a dq moves, then we have to take into account the effects of the movement? The inertia is "attached" to a certain dq.

But if the inertia is "private", why there is no extra inertia from the energy flow between the fields of different dq and -dq? That energy flow would double the inertia change in a radial movement. We have used the energy flow argument to explain extra inertia in a gravity field.


The acceleration imposed by a wire element, using our own conjecture about the inertia inside an electric field



   dl   \     
          
             \        v  =  electron velocity
               v     ρ  =  electron charge per length
          
                     
                                 =  vector (dl, q)
                                r  =  distance (dl, q)

                               
                                  ^  V
                                  |
                                  • q
     ^ y                          m
     |  
      ------> x


Let us determine the acceleration of q in the general case where dl is a wire element. We have protons and electrons in the wire element dl. We will determine the acceleration of q by switching to the comoving frame of the electrons, calculating the acceleration of q there, and Lorentz transforming the acceleration to the laboratory frame.











            dl
               \   dq = electrons
                 \   
                   \   -dq = protons
                 
                       \    v 
                         v


We assume that

       |v|  <<  |V|  <<  c.

We can ignore ~ v² terms and ~ |v| V² terms. The relevant terms are ~ |v| |V|.

The wire element dl contains protons worth a charge -dq, and electrons worth dq. The electrons move along the wire at a velocity v.


In the comoving frame of electrons in the wire.


In the comoving frame of dq, the factor

       γ  =  1 / sqrt(1  -  v² / c²)

           ≅  1  +  1/2 v² / c².

The terms which come from the correction 1/2 v² / c² are ~ v² and can be ignored because we assumed that |v| is small. We can pretend that γ = 1.












Definition. Let us define the effective inertial mass of q under a force F through the formula

       M  =  |F| / |a|.

Note that the force F and the acceleration a may have slightly different directions, because of special relativity. The definition assumes no fields interacting with M. They can alter the inertia.


The effective inertial mass M depends on the relative direction of F and the velocity of q, and the absolute value of the velocity. Generally, the effective inertial mass for a slow velocity V is of a form

       M(F, V)  =  m + C(δ) m V² / c²,

where

       1/2  ≤  C(δ)  ≤  3/2,

and C depends on the angle δ between F and V. We have C = 1/2 if F and V are normal and C = 3/2 if F and V are parallel or antiparallel.

1.   The Coulomb force Fc on q, due to the electric repulsion between dq and q in the comoving frame, is

       Fc  =  1 / (4 π ε₀) * q dq / r² *  r / r,

where r is the vector from dq to q, and r is the length of the vector. We assume that dq and q are both negative charges.

What is the acceleration that Fc causes on q inside the field of dq?

Let Vr be the radial velocity of q relative to dq, and Vt the tangential velocity. The momentum of q is approximately

       p  =  (m + 1/2 m Vr² / c² + 1/2 m Vt² / c²)

                * (Vr, Vt),

where U is the potential energy of the repulsion between dq and q.

The Coulomb force changes the radial velocity and the radial momentum of q.

The derivative of the radial momentum with respect to Vr is

       M  =  m + 1/2 m Vt² / c² + 3/2 m Vr² / c².

That is the "radial inertial mass" of q if we do not include the interaction.

Let Fc push q some distance farther away from dq. Then q gains radial kinetic energy worth some W, and its radial inertial mass would grow by 3 W / c², but since q loses inertia worth 2 W / c², the net gain of inertial mass is W / c². We can pretend that the inertial mass of q is in a radial motion:

      M  =  m  +  1/2 m V² / c².

2.   The inertia of q increases when it dives deeper into the electric field of dq. The test charge q acquires from dq extra inertia which "moves along with dq".

This causes an additional "inertia force" Fi based on the velocity of q:

       Fi  =  -dW / dt  * 1 / (M' c²)  *  (V - v)

             =  -1 / (4 π ε₀) * q dq / r² 

                  *  (V - v) • r / r

                  *  1 / c²  *  (V - v)

             =  -Fc • (V - v) / c²  * (V - v)

             =  -V (Fc • (V - v) / c²)  + v (Fc • V / c²).

Above we use the paradoxical assumption. Otherwise, q would be accelerated to the opposite direction.

We will calculate below that the magnetic field of the wire does not actually change the absolute velocity of q. The above assumption is a hypothesis which makes the mathematics to work, but does not result in any actual speedup.


Switch back to the laboratory frame.

We have to apply the Wikipedia formulae posted above to convert the accelerations to the laboratory frame. We can ignore ~ v² terms.

To obtain the accelerations due to forces, we have to divide by the effective inertial mass M(F, V). A problem is that the angle of F relative to V - v is slightly different from the angle relative to V.

Let us divide the force Fc into the component Fn which is normal to V, and to the (anti)parallel component Fp.

Without the interaction, the inertial mass of q to the direction of V - v is

       m  +  3/2 m (V - v)² / c².

What is its inertial mass to the slightly different direction V? The value of C above is a well-behaved function of the angle between the force and the velocity of q, and the velocity itself. The angle is at most ~|v| / |V|. From the Taylor series for C, we get the result that the inertial mass to the direction of V is

       m  +  (3/2 - C' v²) m (V - v)² / c²,

where C' is essentially a constant for small |v|.

From the Lorentz transformation of an acceleration, we obtain the approximate acceleration due to Fc:

        ac  =  (Fc (1  -  2 v • (V - v) / c²)

                   - Fc • v (V - v) / c²)

                 /  (m + (1/2 - C' v²) m (V - v)² / c²)

             =  (Fc (1  -  2 v • V / c²)  -  V (Fc • v / c²))

                 /  (m + 1/2 m V² / c² - m V • v / c²)

             =  (Fc (1  -  2 v • V / c²)  -  V (Fc • v / c²))

                 / ((m + 1/2 m V² / c²) * (1 - V • v / c²)) 

             =  (Fc (1  -  v • V / c²)  -  V (Fc • v / c²))

                 /  (m + 1/2 m V² / c²).

The first term "1" above is canceled by the corresponding acceleration caused by the protons, -dq, in the wire segment dl. The third term is canceled by the second term in the inertia force:

       ai = (-V (Fc • V / c²)  +  V (Fc • v / c²)

                + v (Fc • V / c²))

              /  (m + 1/2 m V² / c²).

The first term above is canceled by the corresponding inertia force by the protons. The second term is canceled by the third term in ac. We get:

      ai + ac = v (Fc • V / c²)) / (m + 1/2 m V² / c²)

                    - Fc (v • V / c²) / (m + 1/2 m V² / c²).

The Biot-Savart law says that the acceleration should be

       abs  =  q / m * V × 1 / (4 π ε₀) * 1 / c² * 1 / r²

                   * dl ρ v × r / r

               =  1 / c²  *  V × v × Fc / m
         
               =  v (Fc • V / c²) / m

                    - Fc (v • V / c²) / m.

Since V² is very small, it is essentially the same result which we obtained above.


Biot-Savart contradicts the laws of other conventional electromagnetism


Let us have arbitrary moving charges in a system, and a test charge. We can handle each individual charge by switching to its comoving frame and using Coulomb's law. Then switch back to the laboratory frame.

In this way we should obtain the complete electromagnetism, with the magnetic field included. But we know that it is not possible to derive electromagnetism solely from Coulomb's law and special relativity. Thus, conventional electromagnetism contradicts special relativity. Apparently, it is not Lorentz covariant.


Conclusions


Using our hypothesis about the inertia of a test charge, we were able to derive a formula which agrees with Biot-Savart.

We also proved that conventional electromagnetism plus special relativity clash with Biot-Savart and other rules about magnetism. This shows that conventional electromagnetism is self-contradictory. We can expect slight corrections into its rules.

Our calculations about the inertia above ignored the effect of the accelerating movement of the electrons in a wire which is not straight. The drift velocity of electrons in a typical wire is very slow, only a few micrometers per second. The effect of frame dragging or the acceleration of the electrons may be quite small.

Our model explains the orbit of a test charge q close to a wire containing a current. But the model does not describe the (significant) energy and momentum stored in the magnetic field. The Maxwell equations describe the energy and the momentum, at least partially. Classical electromagnetism is silent about the self-force which the Coulomb field of a charge imposes on the charge itself. In our blog we have earlier taken the first steps to model the self-force. Recall our rubber band models of the Coulomb field.

Monday, November 13, 2023

Magnetic field of a rotating sphere calculated by rotating the frame

In August 2023 we tried to calculate the gravity field of a spinning uniform ball, and got varying results. Maybe there were calculation errors? One of the problems was that general relativity, as defined by the Einstein field equations, seems to unable to handle accelerating masses.

On November 6, 2023 we tentatively proved that the Einstein field equations in most cases do not have a solution at all if there are accelerating masses. It might be that general relativity does not determine the field of a rotating body at all.

In literature, it is claimed that the Kerr metric can be derived by studying the Schwarzschild metric in a rotating frame. Let us check what we get if we try to determine the magnetic field of a ball of electric charge by switching to a rotating frame. This is a simple calculation, and we can test experimentally what the magnetic field is like.











(Picture Wikipedia)


The correct magnetic moment of a spinning uniform ball of charge



The magnetic dipole moment of a solid, uniformly charged sphere of uniform density is

       m  =  Q L / (2 m)

             =  Q / m * 1/2 I ω

where Q is the charge, L is the angular momentum, and m is the mass of the sphere. The moment of inertia of the sphere is I and ω is its angular velocity. If we define

       Lₑ  =  Σ q v r

as the "charge angular momentum", then

       m  =  1/2 Lₑ

             =  1/2 Q I / m  *  ω

             =  1/2 Q * 2/5 R² ω

             =  1/5 Q R² ω,

where R is the radius of the ball.









In the equatorial plane, the magnetic field is

       B  =  μ₀ / (4 π)  *  m / r³

            =  μ₀ / (4 π)  *  1/5 Q R² ω /  r³,

where r is the distance from the center. Very close to the surface of the ball the field is

       B  =  μ₀ / (4 π)  *  1/5 Q ω / R

            =  1 / (4 π ε₀)  *  1 / c²  *  1/5 Q ω / R.


A very naive – and wrong – calculation


Let us compare this to a very naive calculation where we assume that the electric field of the ball "moves" at a velocity

       v  =  ω R

at the surface of the ball. At the surface,

       E  =  1 / (4 π ε₀)  *  Q / R².

If v is slow, the magnetic field is

       B  =  1 / c²  *  v × E

            =  1 / (4 π ε₀)  *  1 / c²  *  Q ω / R.

The very naive method gives a magnetic field which is 5X the correct value.


Another naive calculation


            <-- ω
           ___
          /       \   1/4 Q
          \____/
              •  observer


We may approximate the rotating ball with a current loop. Let us assume that 1/4 of Q flows in a circular loop whose radius is R.

Our observer is at

       r  =  R + r'

from the center. We ignore the far side of the loop and assume that the near side is straight. The magnetic field of a straight wire is

       B  =  μ₀ / (4 π)  *  2 I / r',

where I is the electric current and r' the distance from the wire. The current in our case is

       I  =  1/4 Q / (2 π R)  *  R ω.

We obtain

       B  =  1 / (4 π ε₀)  *  1 / c²

                *  Q / (4 π)  *  ω  /  r'.

A reasonable value for r' might be R / 4. We get

       B  =  1 / (4 π ε₀) * 1 / c²  * 1 / π  *  ω / R.

The estimate is 1.6X the correct value.


Yet another naive calculation


The magnetic field primarily rises from the charge moving very close to the observer. Let us guess that such a charge is Q / 10, and it moves at a velocity

       v  =  ω R

at a distance R / 2 from the observer. The magnetic field is then

       B  =  1 / (4 π ε₀)  *  Q / 10  *  4 / R²

                *  1 / c²  *  ω R

            =  1 / (4 π ε₀) * 1 / c²  *  2/5  *  ω / R.

The value is 2X the correct value.


Estimating the gravitomagnetic moment of a rotating sphere: a very naive calculation


Let us first use a very naive method. We assume that we can switch to the rotating frame of the sphere, and in that frame the metric is Schwarzschild.

                  ___
                /       \   M
                \____/   R = radius

                 ^  V
                   \  
                    •  m

The test mass m approaches M, but goes a little bit sideways because m is not spinning along with M. Let us assume that m gathers some extra inertia as it descends, and that inertia is moving along M.

We assume that m is very close to the surface of M, the radius of M is R, and it is rotating at an angular velocity of ω.

If the gravity of M does the work W on m, then m acquires

       W / c²

of extra inertia. That inertia is moving sideways at a velocity

       v  =  ω R.

Let m descend down for a time t. Then

       W =  t V m G M / R²,

and m gets a sideways velocity

       v  =  t V G / c²  * M / R²  *  ω R,

which corresponds to a sideways acceleration

       a  =  V G / c²  *  5/2  * 1 / R³  *  2/5 M R² ω

           =  V * 5/2 G / c² * 1 / R³ * L,

where L is the angular momentum of the sphere. According to our August 10, 2023 definition, the gravitomagnetic moment is then

       mg = 5/2 L.

The moment is 5X the analogous magnetic moment, just like we obtained with a similar very naive method in electromagnetism.


Gravitomgnetic moment: yet another naive calculation


Let us assume that M / 10 is moving at a distance R / 2 from the observer, at a velocity ω R. We can calculate like in the previous section:

       W =  t V m G M / 10  *  4 / R².

We obtain

       mg  =  L,

that is, 2X the analogous electromagnetic moment.


Conclusions


The very naive method, where the entire electric field of a spherical charge is assumed to rotate "fixed" to the rotating sphere, yields a magnetic moment which is 5X too large.

Similarly, using the very naive method to the Schwarzschild metric gives a gravitomagnetic moment which is 5X the analogous electromagnetic moment.

In this blog we have been claiming that the Kerr metric overestimates the gravitomagnetic moment 4X or more. Maybe people doing the Kerr calculations believe that the gravity field rotates "fixed" to the rotating mass?

Our complicated calculations in August and September 2023 brought varying results. A key question is can we add the effects of rotating mass elements linearly?

Our October 18, 2023 blog post suggested that close to the mass M, one cannot obtain the correct Schwarzschild spatial metric by summing the Schwarzschild metric perturbations for each mass element dm. One has to consider the field of M as one "whole".

But that does not mean that if M rotates, then the "whole" field should rotate along with it. The gravitomagnetic effect calculated above depends only on the metric of time, because we calculate the work W done by gravity, and that work comes exclusively from the metric of time. One does obtain the metric of time by linearly adding the perturbations by each mass element.

However, we believe that the 2X extra inertia of a test mass in a radial motion relative to a mass element dm does affect the gravitomagnetic effect, and we did not include that in the calculations above.

On September 4, 2023 we sketched a "unified field theory", where electromagnetism is equivalent to gravity if we ignore the gravity of kinetic energy, of pressure, changes in the spatial metric, and so on. If that hypothesis is correct, then the gravitomagnetic field of a slowly rotating sphere should be exactly analogous to the corresponding electromagnetic field. But we have to check if the correct way to calculate the magnetic field of a rotating electric charge really is the classical one. Our October 9, 2023 blog post suggests that the classical calculation ignores some effects of inertia inside an electric field.

Sunday, November 12, 2023

Does nonlinearity of gravity make sense?

On September 16, 2023 we wrote that nonlinearity of gravity leads to a strange result. Let us analyze this more.

When does the nonlinearity occur? If we have a very large static mass M, then general relativity claims that its gravity is surpringly strong close to M. Let us simulate M with two particles flying to opposite directions at almost the speed of light. The rest mass of the particles is very small, but they have lots of kinetic energy.


                            M
                             
                    v <-- ● 1 
                          2 ● --> v
                             



                              •  m test mass


Let us switch to a comoving frame of the rightmost particle 2. In that frame, the particle 2 is very light and, intuitively, very insignificant. The particle 1 and the test mass m move at almost the speed of light to the left and 1 possesses a lot of energy. We can imagine that m has an infinitesimal rest mass which is infinitesimal even when m moves almost at the speed of light.

But if we would remove the very light particle 2, the acceleration of m would drop to a half. That sounds strange, but is a result of special relativity.


                             ● 2



           v ≅ c    <-- • m


Let us then remove the particle 1. We double the rest mass of 2 and look at the configuration in a comoving frame of 2. In the comoving frame of 2, the particle 2 is very light. Doubling its rest mass certainly cannot have any nonlinear effects.

But in the comoving frame of m, the particle 2 does carry a lot of mass-energy, and there might be nonlinear effects. Do we have a contradiction here?


Conservation of momentum and nonlinearity


How momentum is conserved when fields are retarded? That is an open problem in field theories. Maybe nature performs "transactions" which ensure momentum conservation? Let us check how general relativity is supposed to handle momentum conservation.


The ADM formalism implies conservation of momentum. But we in this blog have tentatively shown that the Einstein field equations do not have any solutions for a typical dynamic system. The ADM formalism assumes that a solution exists.


                    F'                     F
                 ● -->                <----- •
                M                              m


Suppose that we have a very large mass M, such that its gravity is significantly larger than the linear (newtonian) gravity at a test mass m. Then the field of the mass M seems to pull m with a force

       F  >  F',

which is larger than the force that the field of m exerts on M!

This is suspicious. Newton's law of action and reaction is broken? The Einstein-Hilbert action is translation independent. By Noether's theorem, we expect it to conserve momentum. Maybe the existence of the strong field of M makes the field of m non-linear?

Let us use canonical Minkowski space coordinates. General relativity recognizes "proper" momentum, which is measured by a local observer. That differs from coordinate momentum.

Gravitational waves will take away some momentum. The Ricci tensor is zero in them. The Einstein-Hilbert action is not aware of their existence. This implies that momentum is not conserved, unless we define the momentum through some pseudotensor.


Relativity of simultaneousness


                   M
           v <-- ●
                    ● --> v
                   M



                    • m


Let v be very close to c. In the frame of m, the two masses M overlap. But in the comoving frame of the right-moving M, there is very little overlap. Is this compatible with nonlinear gravity?


Nonlinearity from polarization


Imagine that a very strong gravity field pulls positive mass-energy from empty space toward itself, and repels negative mass-energy. That would make gravity steeper than the newtonian 1 / r² gravity.

However, the gravity field close to a huge black hole is not very strong. The polarization hypothesis requires that it is a low potential which produces polarization and not the field strength.

In quantum electrodynamics, vacuum polarization makes the interaction stronger at very short distances, or at very high energies. But that requires energies which are much larger than the mass of the electron, 511 keV. In our blog we hold the view that the vacuum itself is not polarized, but a pair which is born from the energy of a particle collision, simulates vacuum polarization in a scattering experiment.

Can we somehow calculate how much positive/negative mass-energy might pop up if we have a very low gravity potential? That assumes that the vacuum itself can become polarized.


Nonlinearity is needed to satisfy an equivalence principle?


On August 23, 2023 we showed that general relativity breaks the weak equivalence principle. Why should we use nonlinearity to satisfy a certain equivalence principle, when general relativity breaks the most fundamental equivalence principle?


Nonlinearity makes everything complicated


        _____        _____    rubber sheet plane
                  \ ● /
                    M


In a rubber sheet model of gravity, nonlinearity means that the rubber becomes weaker against stretching if it is depressed below the sheet plane more than a certain distance. The weakening is not from the stress on the rubber but from the depth of the depression  –  that is, from a low potential.

Why should it become weaker? Is there some kind of a heater which heats the rubber when it is pressed down a lot?

It is obvious that having a rubber sheet whose strength depends in such a way on the depth of the depression makes calculations complicated if the system is dynamic.


Empirical data


We have to check what is known about accretion disks. Is there any empirical proof that the gravity potential must be steeper than the newtonian one?

In September and October 2023 we showed that the Kerr metric probably is wrong for a rotating black hole. We have to calculate a new solution for a rotating mass and compare empirical data against it.


The paper by Cosimo Bambi (2013) leaves an impression that empirical data does not tell much about the structure of black holes, besides the fact that matter does not hit a solid surface as it is devoured by a black hole.

If gravity is linear, then the Schwarzschild radius is replaced by a Newton radius, which is 1/2 of the Schwarzschild radius. Once we get more accurate measurements of gravitational waves, we may be able to determine what the correct radius is.




















The M87 central black hole (photo Wikipedia)


The Event Horizon Telescope measured the radius of the "photon ring" around the M87 black hole. The margin of uncertainty is given as approximately 10%.


In a Schwarzschild black hole, the lowest circular orbit for a photon is at

       3 G M / c².

In a newtonian black hole, the lowest photon orbit is at

       (1 + sqrt(5))² / 4  * G M / c²

       = 2.62 G M / c².

The data from the Event Horizon Telescope cannot decide which is correct.


Conclusions


There probably is nothing which prevents an interaction from being nonlinear in the sense that a large aggregate charge interacts stronger than the sum of the interactions of its components. We can imagine that the components "help" each other to gain more strength. This certainly is possible in newtonian physics, and we did not find any reason why special relativity would prohibit it.

Nonlinearity creates more "effective charge" for a large mass, when the charge is measured from a short distance. This creation of more charge probably breaks the Einstein equations.

Nonlinearity makes everything complicated and there is no obvious need for nonlinearity. Our own Minkowski-newtonian gravity model works without nonlinearity, though one can add there nonlinearity.

Thursday, November 9, 2023

Calculus of variations and a carpet



















(Photo Wikipedia)

Let us present a simple example where charge conservation keeps the action such that it can be optimized strictly locally, but a change in the charge makes it impossible to optimize the action locally.
                   

                         ___
            ______/ ■■ \_____________    carpet
                      board  -->


We have a long corridor and a carpet which is almost as long as the corridor. Someone forgot a board under the carpet. The board is normal to the corridor and extends from the wall to wall. The volume of the board is a "charge".

The action is the volume V between the floor and the carpet minus the volume of the board under the carpet. Initially the volume V is 0.

If we slide the board along the corridor (i.e., the charge is conserved), we can find the minimum of the action V strictly locally. Just press the carpet tightly to the floor or to the board. This configuration corresponds a typical field theory with charges, like electromagnetism. We can keep the far parts of the carpet as is: the carpet only needs to be adjusted locally.

But if we magically remove the board, the carpet becomes loose. There is a wrinkle, and the action suddenly is V > 0. The charge was not conserved.

We assume that one cannot move the carpet infinitely fast. The action V must stay > 0 for some time.

Now it is obvious that the carpet cannot be optimized strictly locally. We can make V = 0 again by moving the wrinkle to the end of the carpet, but that takes time.

Note that we could have a spare board B which we insert inside the wrinkle. Then we could again optimize the action strictly locally and slide the spare board B out at the end of the carpet. This shows that we can find a solution to the global optimization problem by restoring charge conservation and sliding the spare charge "far away".


                        _
              ____/   \____    carpet
                 wrinkle


Let us study how we can vary the form of the wrinkle in the carpet if there is no board under the carpet. We might have a very large potential which prevents the carpet from curving into a circle of less than, say, 1 cm of radius. We can minimize the volume V under the wrinkle. The optimum is not unique. The wrinkle can be put at many locations. We have a global optimization problem which has many solutions. The solutions do not determine the elevation of the carpet at a specific location.


General relativity


In general relativity, the analogue of the board is a mass M, and the analogue of the carpet is the metric. Suppose that M is a spherically symmetric. Then the field outside M is the Schwarzschild metric.

Suppose that M is suddenly reduced by magic to a mass M' < M. The optimization of the Einstein-Hilbert action suddenly becomes a global problem.

A new optimum, which would satisfy the Einstein field equations, would be the Schwarzschild metric for M'. But we can never get to that metric since the speed of light is finite.

We could use the spare board trick above to switch to the metric of M'. Make a shell of matter whose mass is M - M'. Let that shell recede from M' at the speed of light. However, we can never complete this operation since Minkowski space is infinite.

Conjecture. It is impossible to satisfy the Einstein equations and switch (locally) from the metric of M to the metric of M', if we require the Ricci tensor to be zero in the vacuum around M'. We have to eject some kind of matter to transition to the metric of M'.


In our previous blog post we sketched a proof for this conjecture. The proof uses the "focusing" of a cube of test masses.


Conclusions


The carpet is a "field" and the board is a "charge". We illustrated what happens if we magically reduce the charge. Nice, local optimization conditions are replaced with a much harder global optimization problem.

Monday, November 6, 2023

A single accelerating particle breaks the Einstein field equations?

UPDATE November 30, 2023: In the analysis of the Oppenheimer-Snyder collapse we assumed that Gauss's law for the gravity of a single particle also holds for many particles. This might be false. The inertia of a test mass m inside the common field of all particles in a spherical shell most probably is not the sum of inertias for each individual particle in the shell. We have to check if this destroys Gauss's law for gravity. We wrote about this on October 18, 2023.

----


UPDATE November 30, 2023: For the argument below to work, we have to prove that the "magnetic gravity induction" does not keep the volume of the cube of the test masses constant, after all. Then there would be no "(de)focusing".

Compare to electromagnetism: we can accelerate a charge, and the lines of force of the electric field never break because of the induced magnetic field: there is no "(de)focusing" caused by the electric field. The field equations are not broken in electromagnetism.

The big difference in gravity is that the pressure term ~ v² creates new gravity. We will investigate this in a new blog post.

It might be that Gauss's law for gravity makes the Einstein equations solvable if the pressure term is strictly dependent on the velocity v of the particle. On the other hand, if the pressure changes for some other reason, then Gauss's law is broken, and the Einstein equations have no solution.

Note that acceleration of a particle typically involves some kind of "pressure", and the velocity of the particle does not respond immediately to that pressure. This suggests that Gauss's law is broken in almost all acceleration mechanisms.

----

UPDATE November 10, 2023: The steepening of gravity (nonlinearity) close to a large mass M seems to break the Einstein field equations, too. If we have two masses 1/2 M at some distance from each other, we can increase their combined "focusing power" by moving them very close to each other. That is, the mass-energy charge of the system seems to increase.

A charge is something which occurs in a linear field theory. Any nonlinear effect in gravity may cause focusing or defocusing in "empty" space, and thus make the Ricci tensor non-zero there.

In our own Minkowski-newtonian gravity model there is no obvious reason why gravity should be nonlinear. Maybe gravity, indeed, is a linear phenomenon?

----

In the previous blog post we argued that the Einstein field equations do not have a solution at all if the pressure of a spherically symmetric mass M changes in a way such that the change in the positive pressure is not accompanied by a compensating change of negative pressure.

Ehlers et al. (2005) showed that one can increase the internal pressure of a spherical vessel M if the wall of the vessel obtains a compensating negative pressure. Then the metric outside M does not change, and Birkhoff's theorem is not broken.

We did not yet analyze the non-spherically symmetric case. We believe that the Einstein equations do not have any solution, if the pressure changes and there is no compensating change of negative pressure. Pressure acts as a "charge" which creates gravity. A change in a charge is not tolerated by typical field equations.


The stress-energy tensor T of a moving particle m has a pressure term

       m v²  /  sqrt(1  -  v² / c²)

       * Dirac delta function δ,

where m is the mass of the particle, v is the velocity, and c is the speed of light.

If we speed up the particle, the positive pressure term increases, and there is no compensating change in negative pressure? Is it so that a single accelerating particle breaks the Einstein field equations?

Let us analyze.





















Emmy Noether (1882 - 1935)  (photo Wikipedia)


Conservation laws for a lagrangian



In electromagnetism, conservation of charge is derived from the gauge symmetry:







where X is an arbitrary differentiable real-valued function on the time and the position.


Can we figure out an infinitesimal variation of the Einstein-Hilbert action which would expose the total sum of pressures in a system?







***  













The diagram is from Wikipedia. A spatial translation at t₀ and t₁ exposes the velocity v (= q-dot) of the particle. The diagram is used to prove conservation of momentum.


A temporary stretching of a gravitating system M: can we prove conservation of the "pressure charge"?


Let us stretch a gravitating system M an infinitesimal amount along the x axis, for a short time, and then return it back to the original dimensions.

Let us list changes in the action. The potential energy associated with a positive pressure is reduced for a short time. A negative pressure contributes more potential energy. Parts of the system move slightly during the stretching and unstretching. They contribute changes in the kinetic energy.

We have a problem: the temporary stretching may change many other things in the behavior of M. How can we know that their contribution to the action is neglible?

The above contributions have nothing to do with gravity. They occur in newtonian mechanics, too. They cannot be used to prove conservation of the "pressure charge".

When the pressures change, it may change the gravity field of M. Can we somehow distill the total pressure charge contained inside M?


The Einstein equations probably imply conservation of pressure, while the action does not


It turns out that we are on a wrong track. We suspect that the Einstein field equations imply "conservation of pressure", because they are derived using erroneous variational calculus. On the other hand, the Einstein-Hilbert action probably does not imply conservation of pressure.

In our own Minkowski-newtonian gravity model there is no conservation of pressure. We do not believe that there is conservation of pressure in nature, either.


A simple system where the "pressure" changes


Let us have two equal masses M which are initially static and close to each other. The initial stress-energy tensor is T.

We use some of the mass-energy of both to accelerate them to a fast motion along the x axis, to opposite directions. The masses decline to M' = M / sqrt(1  -  v² / c²).


        •                                     v <--- ●   ● ---> v
       m                                             M' M'

   ----> x


The mass-energy of the system stays as 2 M. After the acceleration, there is a pressure term in the new stress-energy tensor T':

       M' v²  /  sqrt(1  -  v² / c²)
   
       * sum of 2 Dirac delta functions δ.

The sum of momenta is zero.

The metric close to the system must reflect the mass-energy and pressure terms of the new stress-energy tensor T'. But the metric far away still corresponds to T. Can we show that this configuration is impossible?

Let us have a test mass m far away from the M' system, to the negative x direction from the system..

Let us assume that the masses M' are not large.

Hypothesis 1. We can obtain the acceleration of the test mass m by summing the individual gravity fields of each M'.


Hypothesis 2. The changed gravity field of the system spreads at the speed of light. The field corresponding to T is rapidly replaced by the field corresponding to T'.


Hypothesis 3. A "magnetic gravity induction" is not able to connect the lines of force of the gravity field. This hypothesis may be wrong. We will investigate this in a future blog post.


The corrected calculation of our September 9, 2023 blog post shows that the gravity coordinate acceleration due to each M' is as if the mass would be

      M'  /  γ⁵,

where

       γ  =  1 / sqrt(1  -  v² / c²).

When the two masses M were sitting still, the gravity coordinate acceleration of m was as if a mass

       2 M

would be pulling it. After the masses were launched at a velocity v, the "coordinate" attraction is as if a mass

       2 M / γ⁶

would be pulling m. The attractive gravity force declined.


 pull of gravity drops at this
          point, at time t
              <--- c
                     |
                     v
            •   •   • •
            •   •   • •                      v <--- ●  ● ---> v
            •   •   • •                              M'  M'
        test masses


Let us have an initially static cube of test masses floating freely in space. The pull of gravity on the test masses suddenly declines as the field corresponding to T is replaced by the field of T' after the launch. The border between the T metric and T' metric recedes from the M' at the speed of light c.

Does that cause the volume of the cube to decline? If yes, then there is a "focusing" effect, and the Ricci tensor cannot be zero at the cube.

We must also consider the effect of the launch operation itself. The operation involves a pressure between the two M. What kind of a gravity field does that generate? Maybe we do not need to know?

We have to find out the spatial metric at the cube. Maybe the spatial metric expands and compensates the shrinking of the cube? Since the attractive gravity weakens with the introduction of T', most probably the spatial metric shrinks in the direction of the x axis. This makes the cube to shrink even more.

Assumption. The spatial metric change from T to T' shrinks the cube even more.


             •       •       •       •
             
             •       •       •       •                    v <-- ● ● --> v
                                                                   M' M'
             •       •       •       •

                            
      T metric   |    T' metric
               <----- c

    ---> x


Let us create the cube above at a moment when the border between the T and T' metric is in the middle of the cube. That is, we order initially static test masses m in a configuration where the proper distances between the test masses are approximately some fixed s. It is like a cubic crystal system in crystallography. Since the metric is not flat, the crystal cannot be perfect, though.

The border between T and T' moves at the speed of light farther away from the M' system.

Let us wait for a very short time Δt. The left surface of the cube may accelerate much faster in the gravity than the right surface, if the velocity v of the masses M' is large. Does that guarantee that the proper volume of the cube shrinks?

No. If the spatial metric along the x axis would stretch ever more in the transition area between T and T', then the extra stretching could compensate the shrinking of the cube. However, it would be very strange if the spatial metric perturbation would grow as the transition area moves farther from the M' mass system.

Conjecture. The spatial metric perturbation does not grow when the transition moves farther. Rather, the perturbation decreases.


As the cube falls in the gravity, its proper y and z dimensions shrink.

Since the proper volume of the cube shrinks, it must contain very small cubes whose volume shrinks. The metric "focuses" those small cubes. The Ricci tensor cannot be zero there. But the space is empty there and the local stress-energy tensor zero. The Einstein equations then claim that the Ricci tensor is zero. This is a contradiction.

We have a heuristic proof for:

Conjecture 1. The Einstein equations do not have any solution for a simple system which consists of two accelerated masses.


A further conjecture:

Conjecture 2. The Einstein equations do not have a solution for any real-world dynamic physical system. They only have solutions for static systems where pressures do not change, and for some (unrealistic) symmetric dynamic systems.


Yet another:

Conjecture 3. The Einstein equations do not have a solution for any system where two masses orbit each other.


The Oppenheimer-Snyder collapse (1939) does have a solution because it is symmetric



The Oppenheimer-Snyder dust collapse is essentially the only known dynamic solution of the Einstein equations. The solution is spherically symmetric. Oppenheimer and Snyder did not make a calculation error. Let us show that the pressure change (= acceleration of the dust) does not change the Schwarzschild metric outside the collapsing dust ball.

Our updated post on October 11, 2023 contains the conjecture that Gauss's law holds for a moving mass.

Gauss's law conjecture. The average coordinate acceleration of a test mass m at a coordinate distance of r from a moving mass dM is

       G γ dM / r²,

where γ = 1 / sqrt(1  -  v² / c²) and v is the coordinate velocity of dM.


The conjecture says that Gauss's law holds for a moving mass. Its gravitating mass is the mass-energy γ M, as we would expect. The gravity field is not spherically symmetric. The field is weaker in the direction of the movement v and stronger normal to the movement. This is analogous to the field of a moving electric charge.

Let the dust ball start collapsing. At a time t, various dust particles are moving at various velocities v. We can use Gauss's law. The flux of gravity field lines of force through a spherical shell enclosing the collapsing dust cloud is at all times the enclosed mass-energy. The gravity field of the system outside the ball remains the same at all times: we do not encounter the problem of the strength of the field changing.

The field of each dust particle is squeezed in the direction of v, but the configuration is spherically symmetric, and the deformation is not reflected outside the dust ball.

The "simple system" in the previous section is not spherically symmetric. That is why it may break the Einstein equations.

Oppenheimer and Snyder write that they were not able to "integrate" the equations if they add some pressure to the collapsing dust ball. Our conjectures say that the Einstein equations do not have a solution at all in such a case, since they cannot tolerate a change in an "ordinary" pressure where the pressure term does not come from the velocity v of the dust particles. Such pressure would alter gravity outside the dust ball, and break Birkhoff's theorem.


Conclusions


We presented several hypotheses and conjectures about the gravity of various systems. Since the Einstein field equations are nonlinear, it is, in principle, possible that they could work miracles: the nonlinearity could magically restore the integrity, and the Einstein equations would have solutions in many cases. We do not think that they are capable of such magic.

We should present at least heuristic proofs for the conjectures. Since the equations are nonlinear, exact proofs may be hard to construct.

In this blog we have for several years suspected:

1.   general relativity has problems handling changes in pressure;

2.   the Einstein field equations are too strict, and do not have a solution for any realistic physical system.


If our conjectures and arguments are correct, we have shown that we guessed right.